Best Game Eva' - Let's Calculate Gross Tonnage of Imaginary Ships!

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

It could also use an "A" after the "GT" so I can reminisce about Grand Theft Auto.

[MrGoutHimself]

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

I was hoping you'd give us the V... err, oh, wait... Yeah, let's say the ship is a volume of 42,000 m3.

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

I just use google, it will calculate things for you if you search them, even in log10.

Step 1
K = 0.2 + 0.02 × log10(V)
= 0.2 + 0.02 × log10(42,000)
= 0.2 + 0.02 × 4.623
= 0.2 + 0.0925
= 0.2925


Step 2

GT = K × V
= 0.2925 ×42,000
= 12,285

The answer is 12,285...WOO!!

Alright yo, let's find the GT of a ship with a volume of 21,000 cubic meters!

Will it be half of my answer? I don't know and can't wait to find out!

FYI, This game is really brought to you by a miserable cock blocking bitch and for once I'm not talking about me.

[MrGoutHimself]

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

6015.33210379

Not exactly half, but pretty damned close.

Let's try 67,432.

[ThatHaole]

History of the square root of 2

The Babylonian clay tablet YBC 7289 (c. 1800–1600 BC) gives an approximation of √2 in four sexagesimal figures, 1 24 51 10, which is accurate to about six decimal digits,[1] and is the closest possible three-place sexagesimal representation of √2:

1 + \frac{24}{60} + \frac{51}{60^2} + \frac{10}{60^3} = \frac{30547}{21600} = 1.41421\overline{296}.

Another early close approximation is given in ancient Indian mathematical texts, the Sulbasutras (c. 800–200 BC) as follows: Increase the length [of the side] by its third and this third by its own fourth less the thirty-fourth part of that fourth. That is,

1 + \frac{1}{3} + \frac{1}{3 \cdot 4} - \frac{1}{3 \cdot4 \cdot 34} = \frac{577}{408} = 1.41421\overline{56862745098039}.

This ancient Indian approximation is the seventh in a sequence of increasingly accurate approximations based on the sequence of Pell numbers, that can be derived from the continued fraction expansion of √2. Despite having a smaller denominator, it is only slightly less accurate than the Babylonian approximation.

Pythagoreans discovered that the diagonal of a square is incommensurable with its side, or in modern language, that the square root of two is irrational. Little is known with certainty about the time or circumstances of this discovery, but the name of Hippasus of Metapontum is often mentioned. For a while, the Pythagoreans treated as an official secret the discovery that the square root of two is irrational, and, according to legend, Hippasus was murdered for divulging it.

The square root of two is occasionally called "Pythagoras' number" or "Pythagoras' Constant", for example by Conway & Guy (1996).

[MEGADOUCHE]

^^^ what he said.

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

Are you interested in a new game thread?

[amtronic]

Someone needs the "D"
I believe you can calculate the size by girth x length x I dunno, PI?


.

[amtronic]

I calculate cubic inches by the formula --
bore x bore x stroke x #cyl x .786459 = cubic inch displacement
But that's just me.


.

Content, Pictures  and Download links visible to registered users only. 

REGISTER NOW to access all areas that are invisible to non-members.

I think it's girth x length x ???? = Profit.